How to open file from URL with Python

open-url.md

How to open a file from URL with Python

Using urllib.request

# !pip install cairosvg matplotlib pillow

import io
from urllib.request import Request, urlopen
import xml.etree.ElementTree as ET

import cairosvg
import matplotlib.pyplot as plt
from PIL import Image


SVG_URL = "https://upload.wikimedia.org/wikipedia/commons/8/8b/" \
          "Kantone_der_Schweiz.svg"

request = Request(SVG_URL)

with urlopen(request) as response:

    # read and parse SVG file from URL
    svg = ET.parse(io.BytesIO(response.read()))

    canton_zurich = svg.find(".//*[@id='path2536']")

    canton_zurich.set("style", "fill:#12e9a1")

    # get SVG as a string
    svg_string = ET.tostring(svg.getroot())

    # plot with matplotlib
    # see also https://stackoverflow.com/a/70007704/42659
    png = cairosvg.svg2png(svg_string)
    image = Image.open(io.BytesIO(png))
    plt.imshow(image)

Using fsspec

# !pip install cairosvg matplotlib pillow fsspec

import io
from urllib.request import Request, urlopen
import xml.etree.ElementTree as ET

import fsspec

import cairosvg
import matplotlib.pyplot as plt
from PIL import Image


SVG_URL = "https://upload.wikimedia.org/wikipedia/commons/8/8b/" \
          "Kantone_der_Schweiz.svg"

with fsspec.open(SVG_URL) as file:

    # read and parse SVG file from URL
    svg = ET.parse(file)

    canton_zurich = svg.find(".//*[@id='path2536']")

    canton_zurich.set("style", "fill:#12e9a1")

    # get SVG as a string
    svg_string = ET.tostring(svg.getroot())

    # plot with matplotlib
    # see also https://stackoverflow.com/a/70007704/42659
    png = cairosvg.svg2png(svg_string)
    image = Image.open(io.BytesIO(png))
    plt.imshow(image)