Created
March 17, 2014 23:54
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bool wordBreak(string s, unordered_set<string> &dict) { | |
int len = s.length(); | |
if(len==0) return true; | |
if((len == 1) &&(dict.find(s)!=dict.end())) | |
return true; | |
else if(len == 1) | |
return false; | |
int *DPB = new int[len+1]; //DPB[i]=true: substr (start from 0, length=i) breakable, find DPB[len] | |
for(int i=0; i<=len; i++) | |
DPB[i] = false; | |
DPB[0] = true; | |
DPB[1] = (dict.find(s.substr(0,1)) != dict.end()); | |
for(int i=1; i<s.length(); i++) | |
{ | |
for(int j=i; j>=0; j--) | |
{ | |
string sub = s.substr(j, i-j+1); | |
if((dict.find(sub)!=dict.end()) && DPB[j]) | |
{ | |
DPB[i+1]=true; | |
break; | |
} | |
} | |
} | |
bool res = DPB[len]; | |
delete []DPB; | |
return res; | |
} | |
Solution2 | |
class Solution { | |
public: | |
bool wordBreak(string s, unordered_set<string> &dict) { | |
int len = s.length(); | |
vector<bool> dp(len + 1,false); | |
dp[len] = true; | |
for (int i = len - 1; i >= 0; i--) { | |
for (int j = i; j < len; j++) { | |
string str = s.substr(i,j - i + 1); | |
if (dict.find(str) != dict.end() && dp[j + 1]) { | |
dp[i] = true; | |
break; | |
} | |
} | |
} | |
return dp[0]; | |
} | |
}; |
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