Created
November 19, 2017 21:14
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Solución del grupo "josep_pon" de la Semic Challenge de la HackEPS 2017
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#include <algorithm> | |
#include <iostream> | |
#include <fstream> | |
#include <string> | |
const unsigned MAX_NUM = 1000000; | |
const unsigned char NOT_KNOWN = 0; | |
const unsigned char KNOWN_GOOD = 1; | |
const unsigned char KNOWN_BAD = 2; | |
int reverse_integer(int n) | |
{ | |
int reversed_number = 0; | |
int remainder; | |
while(n != 0) | |
{ | |
remainder = n % 10; | |
reversed_number = reversed_number * 10 + remainder; | |
n /= 10; | |
} | |
return reversed_number; | |
} | |
bool is_super_reverse(int n) | |
{ | |
if (n < 10) { return false; } | |
int rev = reverse_integer(n); | |
int sum = rev + n; | |
std::string str = std::to_string(sum); | |
return std::count(str.begin(), str.end(), str[0]) == str.size(); | |
} | |
int main(int argc, char** argv) | |
{ | |
int cases, begin, end; | |
int known_data[MAX_NUM]; | |
int counter = 0; | |
for (int i = 0; i < MAX_NUM; ++i) { | |
if (is_super_reverse(i)) { counter += 1; } | |
known_data[i] = counter; | |
} | |
std::cin >> cases; | |
for (unsigned i = 0; i < cases; ++i) { | |
std::cin >> begin >> end; | |
int count = known_data[end] - known_data[begin]; | |
if (is_super_reverse(begin)) { count += 1; } | |
std::cout << "Case #" << (i + 1) << ": " << count << std::endl; | |
} | |
} |
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