Embedding LUA to an Executable using LuaJIT/FFI via: http://forums.4fips.com/viewtopic.php?f=3&t=589

luajit_ffi_exe.c

/*
(c) 2012 +++ Filip Stoklas, aka FipS, http://www.4FipS.com +++
THIS CODE IS FREE - LICENSED UNDER THE MIT LICENSE
ARTICLE URL: http://forums.4fips.com/viewtopic.php?f=3&t=589
*/

extern "C" {

#include <lua.h>
#include <lualib.h>
#include <lauxlib.h>

} // extern "C"

#include <cassert>

// Please note that despite the fact that we build this code as a regular
// executable (exe), we still use __declspec(dllexport) to export
// symbols. Without doing that FFI wouldn't be able to locate them!

extern "C" __declspec(dllexport) void __cdecl hello_from_lua(const char *msg)
{
    printf("A message from LUA: %s\n", msg);
}

const char *lua_code =
"local ffi = require('ffi')                   \n"
"ffi.cdef[[                                   \n"
"const char * hello_from_lua(const char *);   \n" // matches the C prototype
"]]                                           \n"
"ffi.C.hello_from_lua('Hello from LUA!')      \n" // do actual C call
;

int main()
{
    lua_State *lua = luaL_newstate();
    assert(lua);
    luaL_openlibs(lua);

    const int status = luaL_dostring(lua, lua_code);
    if(status)
        printf("Couldn't execute LUA code: %s\n", lua_tostring(lua, -1));

    lua_close(lua);
    return 0;
}

// output:
// A message from LUA: Hello from LUA!