Computational Methods NB

NB for Chris

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   "cells": [
    {
     "cell_type": "code",
     "collapsed": false,
     "input": "import scipy as sp\nfrom numpy.fft import *",
     "language": "python",
     "metadata": {},
     "outputs": [],
     "prompt_number": 55
    },
    {
     "cell_type": "code",
     "collapsed": false,
     "input": "from matplotlylib import fig_to_plotly\nusername = 'IPython.Demo'\napi_key = '1fw3zw2o13'",
     "language": "python",
     "metadata": {},
     "outputs": [],
     "prompt_number": 56
    },
    {
     "cell_type": "code",
     "collapsed": false,
     "input": "L = 20\nn = 128\nx = linspace(-L/2., L/2., n, endpoint=False)",
     "language": "python",
     "metadata": {},
     "outputs": [],
     "prompt_number": 57
    },
    {
     "cell_type": "code",
     "collapsed": false,
     "input": "fig1 = plt.figure()\nu = exp(-x**2)\nplot(x,u)\nfig_to_plotly(fig1, username, api_key, notebook = True)",
     "language": "python",
     "metadata": {},
     "outputs": [
      {
       "html": "<iframe height=\"500\" id=\"igraph\" scrolling=\"no\" seamless=\"seamless\" src=\"https://plot.ly/~IPython.Demo/2469/600/450\" width=\"650\"></iframe>",
       "metadata": {},
       "output_type": "pyout",
       "prompt_number": 61,
       "text": "<IPython.core.display.HTML at 0x1013a9ad0>"
      }
     ],
     "prompt_number": 61
    },
    {
     "cell_type": "code",
     "collapsed": false,
     "input": "fig2 = plt.figure()\nut = fft(u)\nplot(ut)\nfig_to_plotly(fig2, username, api_key, notebook = True)",
     "language": "python",
     "metadata": {},
     "outputs": [
      {
       "html": "<iframe height=\"500\" id=\"igraph\" scrolling=\"no\" seamless=\"seamless\" src=\"https://plot.ly/~IPython.Demo/2470/600/450\" width=\"650\"></iframe>",
       "metadata": {},
       "output_type": "pyout",
       "prompt_number": 62,
       "text": "<IPython.core.display.HTML at 0x10ddf55d0>"
      }
     ],
     "prompt_number": 62
    },
    {
     "cell_type": "code",
     "collapsed": false,
     "input": "fig3 = plt.figure()\nplot(abs(fftshift(ut)))\nfig_to_plotly(fig3, username, api_key, notebook = True)",
     "language": "python",
     "metadata": {},
     "outputs": [
      {
       "html": "<iframe height=\"500\" id=\"igraph\" scrolling=\"no\" seamless=\"seamless\" src=\"https://plot.ly/~IPython.Demo/2471/600/450\" width=\"650\"></iframe>",
       "metadata": {},
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       "prompt_number": 63,
       "text": "<IPython.core.display.HTML at 0x10de26dd0>"
      }
     ],
     "prompt_number": 63
    },
    {
     "cell_type": "code",
     "collapsed": false,
     "input": "k = (2*pi/L)*r_[linspace(0, n/2-1, n/2), linspace(-n/2,-1,n/2)]",
     "language": "python",
     "metadata": {},
     "outputs": [],
     "prompt_number": 64
    },
    {
     "cell_type": "code",
     "collapsed": false,
     "input": "fig4 = plt.figure()\nplot(fftshift(k), abs(fftshift(ut)))\nfig_to_plotly(fig4, username, api_key, notebook = True)",
     "language": "python",
     "metadata": {},
     "outputs": [
      {
       "html": "<iframe height=\"500\" id=\"igraph\" scrolling=\"no\" seamless=\"seamless\" src=\"https://plot.ly/~IPython.Demo/2473/600/450\" width=\"650\"></iframe>",
       "metadata": {},
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       "prompt_number": 66,
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     "prompt_number": 66
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     "cell_type": "code",
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     "input": "",
     "language": "python",
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