mukulrawat1986/cracklepop.py

Created September 15, 2014 20:05

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Solution to CracklePop problem

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cracklepop.py

	li = ["CracklePop" if i%5==0 and i%3==0 else "Crackle" if i%3==0 else "Pop" if i%5==0 else i for i in xrange(1,101)]
	for i in li:
	print i

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