Created
February 28, 2021 14:01
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algorithm(leetcode) Remove Nth Node From End of List
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func removeNthFromEnd(head *ListNode, n int) *ListNode { | |
head = &ListNode{Next: head} | |
cur, curN := head, head | |
//head.Next == cur.Next => true | |
//cur.Next == curN.Next => true | |
for i := 0; cur != nil; i++ { | |
curN = curN.Next | |
cur = cur.Next | |
if i == n { | |
/* | |
n갯수만큼 돌다가 다시 초기화해주면, | |
for문이 다 돌았을 때 해당 curN은 삭제할 인덱스 바로 직전에 위치함 | |
*/ | |
curN = head | |
} | |
} | |
curN.Next = curN.Next.Next //두번 건너뛰면 삭제할 수 있음 | |
return head.Next | |
} |
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