isMobileNo_MoreThan1Number.py

import re

def isMobileNumber(sentence):
  mobileNumberPattern = re.compile("(91[6-9][0-9]{9})")
  number = mobileNumberPattern.findall(sentence)
  return number

sentence = "My mobile no is 918344777333 and 918883775533, 91234567890"
mobileNumber_present = isMobileNumber(sentence)
print(type(mobileNumber_present))

for number in mobileNumber_present:
  print(number)