My Leetcode Problem Solutions

Reverse-Integer.kt

// O(n)
class Solution {
    fun reverse(x: Int): Int {
        var reversed = 0
        var number = x

        while (number != 0) {
            val remainder = number % 10

            reversed = reversed * 10 + remainder

            if (isBiggerThanLimit(reversed, remainder) && number != 0) {
                return 0
            }

            number -= remainder
            number /= 10
        }

        return reversed
    }

    private fun isBiggerThanLimit(reversed: Int, remainder: Int): Boolean {
        return if (reversed < 0) {
            reversed < Int.MIN_VALUE / 10 - remainder
        } else {
            reversed >= Int.MAX_VALUE / 10 - remainder
        }
    }
}