Non-submitted solution for COhPy's 201602 challenge, (https://github.com/cohpy/challenge-201602-leapday).

201602.py

#!/usr/bin/env python3

## This works in Python 2 and Python 3

import datetime as dt

for x in range(2020, 1000000, 4):
    t = dt.datetime(x, 2, 29)
    if t.weekday() == 0:
        print("Found it! {0}".format(x))
        break