pythonchallenge.com solutions (1 to 5)

pythonchallenge-1to5.py

# I kept solving the puzzles until I reached the donation page. I give up. No dollars please.

################################################################################
# For challenge 5

def challenge5():
    import pprint
    import pickle 
    
    f = open('banner.p', 'rb')

    for line in pickle.load(f):
        print ''.join(map(lambda pair: pair[0]*pair[1], line))
        
    
    
################################################################################
# For challenge 4

def challenge4():
    import re
    import urllib

    url = "http://www.pythonchallenge.com/pc/def/linkedlist.php?nothing="

    i = 63579

    while 1:
        print "Trying url = " + url + str(i)
        u = urllib.urlopen(url + str(i))
        s = u.read()
        print '\t' + s
        print
        i = re.findall(r'([0-9]+)', s)[0]
        u.close()



################################################################################
# For challenge 3

def challenge3():
    import re
    import urllib

    u = urllib.urlopen("http://www.pythonchallenge.com/pc/def/equality.html")
    thestring = u.read()
    u.close()

    thestring = thestring.split('\n')
    thestring = thestring[22:1271]
    thestring = "".join(thestring)

    # print thestring

    # p = re.compile(r'(\w)\1{2}[a-z](\w)\2{2}')
    #print p.search('the is a good boy the the tt UUUiYYYAAAaTYW KKKjOPS OSHzRTQQ').group()
    #'the the'
    print re.findall(r'[a-z][A-Z][A-Z][A-Z]([a-z])[A-Z][A-Z][A-Z][a-z]', thestring)
    # print p.search(thestring).group()



################################################################################
# For challenge 2

def challenge2():
    import collections

    import urllib

    u = urllib.urlopen("http://www.pythonchallenge.com/pc/def/ocr.html")
    thestring = u.read()
    u.close()

    thestring = thestring.split('\n')
    thestring = thestring[38:1257]
    thestring = "".join(thestring)

    print thestring

    d = collections.defaultdict(int)
    for c in thestring:
        d[c] += 1
    
    for c in sorted(d, key=d.get, reverse=True):
      print '%s %6d' % (c, d[c])





################################################################################
# For challenge 1

def challlenge1():
    from string import maketrans   

    a = "g fmnc wms bgblr rpylqjyrc gr zw fylb. rfyrq ufyr amknsrcpq ypc dmp. bmgle gr gl zw fylb gq glcddgagclr ylb rfyr'q ufw rfgq rcvr gq qm jmle. sqgle qrpgle.kyicrpylq() gq pcamkkclbcb. lmu ynnjw ml rfc spj."

    # b = ""
    it = 'abcdefghijklmnopqrstuvwxyz'
    ot = 'cdefghijklmnopqrstuvwxyzab'
    tt = maketrans(it, ot)

    # for c in a:
    #     x = c
    #     
    #     if c.isalnum():
    #         if c == 'y':
    #             x = 'a'
    #         elif c == 'z':
    #             x = 'b'
    #         else:
    #             x = chr(ord(c) + 2)
    #     
    #     b = b + x

    print a.translate(tt)
    print "http://www.pythonchallenge.com/pc/def/map.html".translate(tt)
    # print b