Created
September 29, 2015 13:17
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MergeSort in C# - by Nakov
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using System; | |
public class MergeSortExample | |
{ | |
public static void Main(string[] args) | |
{ | |
int[] array = { 5, 9, 2, 3, 6, -7 }; | |
Console.WriteLine("Unsorted: [{0}]", string.Join(", ", array)); | |
var sortedArr = MergeSort(array, 0, array.Length - 1); | |
Console.WriteLine("Sorted (Merge Sort): [{0}]", string.Join(", ", sortedArr)); | |
} | |
private static int[] MergeSort(int[] array, int start, int end) | |
{ | |
if (start < end) | |
{ | |
int middle = (end + start) / 2; | |
int[] leftArr = MergeSort(array, start, middle); | |
int[] rightArr = MergeSort(array, middle + 1, end); | |
int[] mergedArr = MergeArray(leftArr, rightArr); | |
return mergedArr; | |
} | |
return new int[] { array[start] }; | |
} | |
private static int[] MergeArray(int[] leftArr, int[] rightArr) | |
{ | |
int[] mergedArr = new int[leftArr.Length + rightArr.Length]; | |
int leftIndex = 0; | |
int rightIndex = 0; | |
int mergedIndex = 0; | |
// Traverse both arrays simultaneously and store the smallest element of both to mergedArr | |
while (leftIndex < leftArr.Length && rightIndex < rightArr.Length) | |
{ | |
if (leftArr[leftIndex] < rightArr[rightIndex]) | |
{ | |
mergedArr[mergedIndex++] = leftArr[leftIndex++]; | |
} | |
else | |
{ | |
mergedArr[mergedIndex++] = rightArr[rightIndex++]; | |
} | |
} | |
// If any elements remain in the left array, append them to mergedArr | |
while (leftIndex < leftArr.Length) | |
{ | |
mergedArr[mergedIndex++] = leftArr[leftIndex++]; | |
} | |
// If any elements remain in the right array, append them to mergedArr | |
while (rightIndex < rightArr.Length) | |
{ | |
mergedArr[mergedIndex++] = rightArr[rightIndex++]; | |
} | |
return mergedArr; | |
} | |
} |
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This is a great piece of work. You just saved my day. Thank you.