Sorting a dictionary by value

sorting_dictionary_by_value.py

# Given a dictionary
>>> ds = {'a': 4, 'b': 3, 'c': 2, 'd': 1}
>>> sorted(ds.items(), key=lambda y:y[1])   ## sorts values in ascending order 

'''Result'''
[('d', 1), ('c', 2), ('b', 3), ('a', 4)]

# Or we can use itemgetter to sort by any item

from operator import itemgetter

>>> sorted(ds.items(), key=itemgetter(1))   ## sorts values in ascending order yields same result as above

'''Result'''
[('d', 1), ('c', 2), ('b', 3), ('a', 4)]