Skip to content

Instantly share code, notes, and snippets.

What would you like to do?
class LinkedList:
next = None
val = None
def __init__(self, val):
self.val = val
def add(self, val):
if == None: = LinkedList(val)
def __str__(self):
return "({val}) ".format(val=self.val) + str(
class BinaryTree:
val = None
left = None
right = None
def __init__(self, val):
self.val = val
def __str__(self):
return "<Binary Tree (val is {val}). \n\tleft is {left} \n\tright is {right}>".format(val=self.val, left=self.left, right=self.right)
def depth(tree):
if tree == None:
return 0
if tree.left == None and tree.right == None:
return 1
depthLeft = 1+depth(tree.left)
depthRight = 1+depth(tree.right)
if depthLeft > depthRight:
return depthLeft
return depthRight
def tree_to_linked_lists(tree, lists={}, d=None):
if d == None:
d = depth(tree)
if lists.get(d) == None:
lists[d] = LinkedList(tree.val)
if d == 1:
return lists
if tree.left != None:
lists = tree_to_linked_lists(tree.left, lists, d-1)
if tree.right != None:
lists = tree_to_linked_lists(tree.right, lists, d-1)
return lists
if __name__ == '__main__':
mainTree = BinaryTree(1)
someSubTrees = {"left": BinaryTree(2), "right": BinaryTree(3)}
someSubTrees["left"].left = BinaryTree(4)
someSubTrees["left"].right = BinaryTree(5)
someSubTrees["right"].left = BinaryTree(6)
someSubTrees["right"].right = BinaryTree(7)
someSubTrees["right"].right.right = BinaryTree(8)
someSubTrees["left"].left.left = BinaryTree(9)
mainTree.left = someSubTrees["left"]
mainTree.right = someSubTrees["right"]
ttll = tree_to_linked_lists(mainTree)
for depthLevel, linkedList in ttll.iteritems():
print "{0} {1}".format(depthLevel, linkedList)
Sign up for free to join this conversation on GitHub. Already have an account? Sign in to comment