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Interview question for recurse center. Depth First Search in Python.
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import string | |
def dfs(tree, element): | |
"""An iterative implementation of depth first search. It returns the element in question | |
if it is present and none otherwise. | |
""" | |
visited = set() | |
stack = [tree] | |
while stack: | |
current_node = stack.pop() | |
visited.add(current_node) | |
if current_node.data == element: | |
return element | |
elif current_node.children is not None: | |
for node in current_node.children: | |
if node not in visited: | |
stack.append(node) | |
def bfs(element): | |
"""Breadth First Search TODO::""" | |
pass | |
class Node(object): | |
def __init__(self, children = None, data=None): | |
self.children = children | |
self.data = data | |
def add_child(self, node): | |
if not self.children: | |
self.children = [node] | |
else: | |
self.children.append(node) | |
def add_children(self, nodes): | |
if not self.children: | |
self.children = nodes | |
else: | |
self.children += nodes | |
def create_test_tree(): | |
"""This method creates a tree with all of the letters in the alphabet present for testing purposes""" | |
root = Node(data='a') | |
current_node = root | |
for i, letter in enumerate(string.ascii_lowercase[1:]): | |
new_tree = Node(data=letter) | |
current_node.add_child(new_tree) | |
if i == 13: | |
current_node = root | |
elif i % 2 == 0: | |
current_node = new_tree | |
return root | |
tree = create_test_tree() | |
print(dfs(tree, 'a')) | |
print(dfs(tree, 'b')) | |
print(dfs(tree, 'w')) | |
print(dfs(tree, 'aaa')) |
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