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#include <iostream>
using namespace std;


bool is_int(string number) {
    bool after_dot = false;
    for (char c : number) {
        if (after_dot and c != '0') {
            return false;
        } else if (c == '.') {

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array[1..3] of int: divisors = [2, 3, 7];

var 1..100: answer;

constraint forall(d in divisors)( answer mod d == 0 );

solve satisfy;

output [ "The ultimate answer is \(answer).\n" ];

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\NeedsTeXFormat{LaTeX2e}
\ProvidesClass{independent-study}

\DeclareOption*{\PassOptionsToClass{\CurrentOption}{book}}
\ProcessOptions\relax
\LoadClass[11pt,a4paper,oneside]{book}


% thai book
\usepackage[english,thai]{babel}

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#!/usr/bin/env Rscript

library(rgl)
library(sp)


calc_radian <- function(i, tick, uplim) {
    2 * pi * (i / tick) * (uplim / 360)
}

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random.int <- function(n) { sample.int(n, 1) }


random.coupon <- function(...) {
  count <- 0
  have.coupon <- logical(...)
  while (!all(have.coupon)) {
    have.coupon[random.int(...)] <- TRUE
    count <- count + 1
  }

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Break the NSA Encryption

`Challenge on Gist`_ from `this Facebook Post`_ provide an interesting question on cracking the NSA encryption. Doesn't this hook you enough? Let's roll. :D

Note, you can also test the validity of logic in this file with the command:

$ python3 -m doctest break_nsa.rst --verbose