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HW5.pl
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% Nicholas Nelson (931-242-585) | |
% | |
% CS 381: Homework 5 | |
% 6.2.2015 | |
% | |
% Here are a bunch of facts describing the Simpson's family tree. | |
% Don't change them! | |
female(mona). | |
female(jackie). | |
female(marge). | |
female(patty). | |
female(selma). | |
female(lisa). | |
female(maggie). | |
female(ling). | |
male(abe). | |
male(clancy). | |
male(herb). | |
male(homer). | |
male(bart). | |
married_(abe,mona). | |
married_(clancy,jackie). | |
married_(homer,marge). | |
married(X,Y) :- married_(X,Y). | |
married(X,Y) :- married_(Y,X). | |
parent(abe,herb). | |
parent(abe,homer). | |
parent(mona,homer). | |
parent(clancy,marge). | |
parent(jackie,marge). | |
parent(clancy,patty). | |
parent(jackie,patty). | |
parent(clancy,selma). | |
parent(jackie,selma). | |
parent(homer,bart). | |
parent(marge,bart). | |
parent(homer,lisa). | |
parent(marge,lisa). | |
parent(homer,maggie). | |
parent(marge,maggie). | |
parent(selma,ling). | |
%% | |
% Part 1. Family relations | |
%% | |
% 1. Define a predicate `child/2` that inverts the parent relationship. | |
child(A,B) :- parent(B,A). | |
% 2. Define two predicates `isMother/1` and `isFather/1`. | |
isMother(A) :- parent(A,_), female(A). | |
isFather(A) :- parent(A,_), male(A). | |
% 3. Define a predicate `grandparent/2`. | |
grandparent(A,B) :- parent(A,X), parent(X,B). | |
% 4. Define a predicate `sibling/2`. Siblings share at least one parent. | |
sibling(A,B) :- parent(X,A), parent(X,B), A \= B. | |
% 5. Define two predicates `brother/2` and `sister/2`. | |
brother(A,B) :- sibling(A,B), male(A). | |
sister(A,B) :- sibling(A,B), female(A). | |
% 6. Define a predicate `siblingInLaw/2`. A sibling-in-law is either married to | |
% a sibling or the sibling of a spouse. | |
siblingInLaw(A,B) :- married(A,X), sibling(X,B). | |
siblingInLaw(A,B) :- sibling(A,X), married(B,X). | |
% 7. Define two predicates `aunt/2` and `uncle/2`. Your definitions of these | |
% predicates should include aunts and uncles by marriage. | |
aunt(A,B) :- sibling(A,X), parent(X,B), female(A). | |
aunt(A,B) :- siblingInLaw(A,X), parent(X,B), female(A). | |
uncle(A,B) :- sibling(A,X), parent(X,B), male(A). | |
uncle(A,B) :- siblingInLaw(A,X), parent(X,B), male(A). | |
% 8. Define the predicate `cousin/2`. | |
cousin(A,B) :- sibling(X,Y), parent(X,A), parent(Y,B). | |
% 9. Define the predicate `ancestor/2`. | |
ancestor(A,B) :- parent(A,B). | |
ancestor(A,B) :- parent(A,X), ancestor(X,B). | |
% Extra credit: Define the predicate `related/2`. | |
descendent(A,B) :- ancestor(B,A). | |
relatedP(A,B) :- married(A,B). | |
relatedP(A,B) :- ancestor(A,B). | |
relatedP(A,B) :- descendent(A,B). | |
related(A,B) :- relatedP(A,B), A \= B. | |
related(A,B) :- relatedP(A,X), relatedP(X,B), A \= B. | |
%% | |
% Part 2. List manipulation | |
%% | |
% 10. Define a predicate `rdup(L,M)` that removes adjacent duplicate elements | |
% from the list `L`. The resulting list should be bound to `M`. It's OK if | |
% this function loops on queries where `L` is not provided. | |
rdup([],[]). | |
rdup([L],[L]). | |
rdup([L,L|R],R2) :- rdup([L|R],R2). | |
rdup([L,X|R],[L|R2]) :- L \= X, rdup([X|R],R2). |
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