The below function is written to check whether a given three digit number is an Armstrong number. Hint: An “Armstrong number” is an n-digit number that is equal to the sum of the nth powers of its individual digits. Example: 371 is an Armstrong number as 371 = 3^3 +7^3+ 1^3

#PF-Assgn-45.py

'''
Created on 24-Aug-2019

@author: Anonymous
'''
#PF-Tryout
def find_armstrong(number):
    temp=0
    x=number #
    while(number!=0):
        remainder=number%10
        # This Statement changing the value of number variable so 
        number=number//10
        # For keeping original Number we took it in a variable named a "x"
        temp+=(remainder*remainder*remainder)
    if(x==temp):
        return True
    return False

number=371
if(find_armstrong(number)):
    print(number,"is an Armstrong number")
else:
    print(number,"is not an Armstrong number")