Last active
September 13, 2022 08:38
-
-
Save nhatminhbui/bf17b57dc289667100bbdf473731383c to your computer and use it in GitHub Desktop.
check.py
This file contains bidirectional Unicode text that may be interpreted or compiled differently than what appears below. To review, open the file in an editor that reveals hidden Unicode characters.
Learn more about bidirectional Unicode characters
def check(A, r, c): | |
""" | |
ARGs: | |
- tick position | |
RETURN: | |
boolean | |
""" | |
global win_array | |
# row | |
cbw = c | |
cfw = c | |
neighbor = 1 | |
while (neighbor <= 4 | |
and cbw > 0 and cfw < len(A)-1): | |
if A[r][cbw-1] == 1: cbw -= 1 | |
if A[r][cfw+1] == 1: cfw += 1 | |
neighbor += 1 | |
if distance(r, cbw, r, cfw) == 16: | |
for i in range(5): # construct array | |
win_array.append((r, cbw+i)) | |
return True | |
# col | |
ruw = r | |
rdw = r | |
neighbor = 1 | |
while (neighbor <= 4 | |
and ruw > 0 and rdw < len(A)-1): | |
if A[ruw-1][c] == 1: ruw -= 1 | |
if A[rdw+1][c] == 1: rdw += 1 | |
neighbor += 1 | |
if distance(ruw, c, rdw, c) == 16: | |
for i in range(5): | |
win_array.append((ruw+i, c)) | |
return True | |
# diag | |
ulr, ulc = r, c | |
drr, drc = r, c | |
neighbor = 1 | |
while (neighbor <= 4 | |
and ulr > 0 and ulc > 0 | |
and drr < len(A)-1 and drc < len(A)-1): | |
if A[ulr-1][ulc-1] == 1: | |
ulr -= 1; ulc -= 1 | |
if A[drr+1][drc+1] == 1: | |
drr +=1; drc +=1 | |
neighbor += 1 | |
if distance(ulr, ulc, drr, drc) == 32: | |
for i in range(5): | |
win_array.append((ulr+i, ulc+i)) | |
return True | |
# anti-diag | |
urr, urc = r, c | |
dlr, dlc = r, c | |
neighbor = 1 | |
while (neighbor <= 4 | |
and urr > 0 and urc < len(A)-1 | |
and dlr < len(A)-1 and dlc > 0): | |
if A[urr-1][urc+1] == 1: | |
urr -= 1; urc += 1 | |
if A[dlr+1][dlc-1] == 1: | |
dlr += 1; dlc -= 1 | |
neighbor += 1 | |
if distance(urr, urc, dlr, dlc) == 32: | |
for i in range(5): | |
win_array.append((urr+i, urc-i)) | |
return True | |
return False |
Sign up for free
to join this conversation on GitHub.
Already have an account?
Sign in to comment