Question:
write a function maskify, which changes all but the last four characters into '#'
Eg:
maskify('4556364607935616') # should return '############5616'
maskify('64607935616') # should return '#######5616'
maskify('1') # should return '1'
maskify('') # should return ''
Answer:
function maskify(input){
return input.replace(/.(?=....)/g, '#')
}