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// Linear scrollTo

// used more than once, so better off in function
const getNowTimestamp = () => (
    'now' in window.performance ? performance.now() : +new Date
);
const scrollTo = (dest, duration = 300, callback) => {
    const body = document.body,
        docElement = document.documentElement;

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// return the factorial
const fact = (f) => (
  Array.from({length: f}, (v, i) => i + 1).reduce((sum, v) => sum *= v, 1)
)

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const fibo = (() => {
  
  let memo = {};
  
  const _fibo = (n) => {
    console.time();
    let value;
    if (n in memo) {
      value = memo[n];
    } else {

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const sumToN = (n) => ( n * (n + 1) / 2 )

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function checkBalanced(str, openChar = '(', closeChar = ')') {
  // validate input
  if (!str || !str.trim().length) {
    return false;
  }
  
  const matches = str.match(new RegExp(`(\\${openChar}|\\${closeChar})`, 'g'));

  // check for odd #
  if (matches.length % 2 !== 0) {

nicholasaiello

const input = "who tried never Made anything a A Mistake never New Person.",
      stripPunctuation = (str) => str.replace(/[\.\,\?\-\_\!]/, ''),
      isLowerCase = (str) => !(str.charCodeAt(0) >= 65 && str.charCodeAt(0) <= 90),
      format = (arr) => arr.reverse().join(' ')

const sortFn = (a, b) => {

  if (isLowerCase(a) && isLowerCase(b)) {
    return a.localeCompare(b) * -1;

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// Given a string "aaabbbccdeff", compress it, = "a3b3c2def2"

const input = "aaabbbccdeff";

function compressWord(str = '') {
  const size = (str || '').length;
  // edge cases
  if (size < 2) {
    return str;
  } else if (size === 2) {

nicholasaiello

/**
  determine character frequency of provided input: ex, "chicago"
  print the frequency as follows
  
  c: **
  h: *
  i: *
  a: *
  g: *
  o: *

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const words = ['map', 'art', 'how', 'rat', 'tar', 'who', 'pam', 'shoop'];

const sortWord = (word) => (
  word.split('').sort().join('')
);

const matches = words.reduce((obj,w) => {
  if (w) {
    const k = sortWord(w);
    if (!(k in obj)) {

nicholasaiello

const powerOfTwo = (num) => (
  (num & (num - 1)) === 0
)