Created
June 1, 2012 23:46
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Math riddle: 4 = 3
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| Theorem: 3=4 | |
| Proof: | |
| Suppose: | |
| a + b = c | |
| This can also be written as: | |
| 4a - 3a + 4b - 3b = 4c - 3c | |
| After reorganizing: | |
| 4a + 4b - 4c = 3a + 3b - 3c | |
| Take the constants out of the brackets: | |
| 4 * (a+b-c) = 3 * (a+b-c) | |
| Remove the same term left and right: | |
| 4 = 3 |
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