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PHP: Get Distance Between two Geolocated Points (lat/lon)
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<?php | |
/* These are two points in New York City */ | |
$point1 = array('lat' => 40.770623, 'long' => -73.964367); | |
$point2 = array('lat' => 40.758224, 'long' => -73.917404); | |
$distance = getDistanceBetweenPoints($point1['lat'], $point1['long'], $point2['lat'], $point2['long']); | |
foreach ($distance as $unit => $value) { | |
echo $unit.': '.number_format($value,4).'<br />'; | |
} | |
/* | |
Output: | |
miles: 2.6025 | |
feet: 13,741.4350 | |
yards: 4,580.4783 | |
kilometers: 4.1884 | |
meters: 4,188.3894 | |
*/ |
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<?php | |
/** | |
* Calculates the distance between two points, given their | |
* latitude and longitude, and returns an array of values | |
* of the most common distance units | |
* | |
* @param {coord} $lat1 Latitude of the first point | |
* @param {coord} $lon1 Longitude of the first point | |
* @param {coord} $lat2 Latitude of the second point | |
* @param {coord} $lon2 Longitude of the second point | |
* @return {array} Array of values in many distance units | |
*/ | |
function getDistanceBetweenPoints($lat1, $lon1, $lat2, $lon2) { | |
$theta = $lon1 - $lon2; | |
$miles = (sin(deg2rad($lat1)) * sin(deg2rad($lat2))) + (cos(deg2rad($lat1)) * cos(deg2rad($lat2)) * cos(deg2rad($theta))); | |
$miles = acos($miles); | |
$miles = rad2deg($miles); | |
$miles = $miles * 60 * 1.1515; | |
$feet = $miles * 5280; | |
$yards = $feet / 3; | |
$kilometers = $miles * 1.609344; | |
$meters = $kilometers * 1000; | |
return compact('miles','feet','yards','kilometers','meters'); | |
} |
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