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Python script to break large XML files
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import os | |
import sys | |
from xml.sax import parse | |
from xml.sax.saxutils import XMLGenerator | |
class CycleFile(object): | |
def __init__(self, filename): | |
self.basename, self.ext = os.path.splitext(filename) | |
self.index = 0 | |
self.open_next_file() | |
def open_next_file(self): | |
self.index += 1 | |
self.file = open(self.name(), 'w') | |
def name(self): | |
return '%s%s%s' % (self.basename, self.index, self.ext) | |
def cycle(self): | |
self.file.close() | |
self.open_next_file() | |
def write(self, str): | |
self.file.write(str) | |
def close(self): | |
self.file.close() | |
class XMLBreaker(XMLGenerator): | |
def __init__(self, break_into=None, break_after=1000, out=None, *args, **kwargs): | |
XMLGenerator.__init__(self, out, encoding='utf-8', *args, **kwargs) | |
self.out_file = out | |
self.break_into = break_into | |
self.break_after = break_after | |
self.context = [] | |
self.count = 0 | |
def startElement(self, name, attrs): | |
XMLGenerator.startElement(self, name, attrs) | |
self.context.append((name, attrs)) | |
def endElement(self, name): | |
XMLGenerator.endElement(self, name) | |
self.context.pop() | |
if name == self.break_into: | |
self.count += 1 | |
if self.count == self.break_after: | |
self.count = 0 | |
for element in reversed(self.context): | |
self.out_file.write("\n") | |
XMLGenerator.endElement(self, element[0]) | |
self.out_file.cycle() | |
XMLGenerator.startDocument(self) | |
for element in self.context: | |
XMLGenerator.startElement(self, *element) | |
filename, break_into, break_after = sys.argv[1:] | |
parse(filename, XMLBreaker(break_into, int(break_after), out=CycleFile(filename))) |
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Thanks for sharing this script! It works so well!