lambda.py

# with lambda
pkg_dict['resources'] = filter(lambda x: x.get('id') != id, pkg_dict.get('resources', []))

#without lambda
for res in pkg_dict.get('resources', []):                                   
    if res.get('id') == id:
        pkg_dict['resources'].remove(id) 

Can't you do something like

pkg_dict['resources'] = [x.get('id') for x in pkg_dict.get('resources', []) if x.get('id') != id]

Like the filter option better ;) - since id is the key can't you convert this to a dict and then access by id?

Note only works if you don't have multiple resources per id (don't know your data)

pd=dict((x.get('id'),x) for x in pkg_dict.get('resources',[]))
return pd.get(id)