phase 0 unit 2 week 1 boggle class challenge

0.2.1-boggle_class_from_methods.rb

class BoggleBoard

  def initialize(board) #this means we can have more than one board
    @board = board
  end

  def create_word(*coords)
    coords.map { |coord| @board[coord.first][coord.last]}.join("")
  end

  def get_row(row)
    puts @board[row].join("")
  end

  def get_col(col)
    puts @board.transpose[col].join("")
  end

  def get_coord(coord1, coord2)
    puts @board[coord1][coord2]
  end

end

dice_grid =      [["b", "r", "a", "e"],
                  ["i", "o", "d", "t"],
                  ["e", "c", "l", "r"],
                  ["t", "a", "k", "e"]]

boggle_board = BoggleBoard.new(dice_grid)
puts boggle_board.create_word([1,2], [1,1], [2,1], [3,2]) #=> dock
boggle_board.get_row(0) #=> brae
boggle_board.get_row(1) #=> iodt
boggle_board.get_row(2) #=> eclr
boggle_board.get_row(3) #=> take
boggle_board.get_col(0) #=> biet
boggle_board.get_col(1) #=> roca
boggle_board.get_col(2) #=> adlk
boggle_board.get_col(3) #=> etre

boggle_board.get_coord(3, 2)

#Reflection
=begin
 This was very similar to the last exercise that I just completed. I thought that it was easier to write in object-oriented programming
 because now I can have multiple instances of a boggle board instead of just one. Right now all I am still not able to figure out how to
 write a get_diagonal method other than thinking about the pseudo code. Right now all I have figured out is that I should probably first check
 that the coordinated given are the corners of the board to that it would actually be a diagonal. And in this case I could write a 
  raise argument error if the coordinates are not the corners of the board. Until then I will update this gist as I go
  
=end