Compute the maximum storage size given some conditions and the time to reach it

gas.py

#!/usr/bin/env python3

precommitGas = 9000000
provecommitGas = 40000000
windowpostGas = 512265727
windowPostInPartition = 2349
sectorSize = 32

blockLimitGas = 10e9

percPreCommit = 0.33
percProveCommit = 0.33
percWindowPost = 0.33

tipset = 5

def howManyTx(gasTx,proportion):
    return blockLimitGas * proportion / gasTx

def gbToEB(gb):
    return gb/1024/1024/1024

def ebToGB(eb):
    return eb * 1024 * 1024 * 1024

## how many windowpost in a day
nbWindowPost = howManyTx(windowpostGas, percWindowPost) * tipset * 2 * 60 * 24
## how much storage does this represents in EB
storageWPost = gbToEB(nbWindowPost * windowPostInPartition * sectorSize)

## how many precommit in a block
nbPreCommit = howManyTx(precommitGas, percPreCommit)
## how many provecommit in a block
nbProveCommit = howManyTx(provecommitGas, percProveCommit)
## we take the min to be able to determine the soonest the amount of storage is
## fully emboarded. For example if we can put 133 PreCommit but 150 ProveCommit,
## we still need to wait to emboard 133 PreCommit each time, so it's longer
nbEmboardTx = min(nbPreCommit,nbProveCommit)
## how many rounds do we need to reach the size representable with window posts
rounds = ebToGB(storageWPost) / (nbEmboardTx * sectorSize * tipset)
## how much time does this represents
timeMonths = rounds / (2 * 60 * 24 * 30)

print("Number of window posts in a day: ",nbWindowPost)
print("Can reach max storage: ",storageWPost, "(EB)")
print("Number of rounds to to reach that storage: ",rounds)
print("In months: ",timeMonths)