Coffee-script fizzbuzz. Just had to try and make one after reading this: http://www.codinghorror.com/blog/2007/02/why-cant-programmers-program.html

coffee-script-fizzbuzz.coffee

for i in [1..100]
  if i % 3 is 0 and i % 5 is 0 then console.log "FizzBuzz"
  else if i % 3 is 0 then console.log "Fizz"
  else if i % 5 is 0 then console.log "Buzz"
  else console.log "#{i}"

La oss ta et rekursivt eksempel, because:

def fizzbuzz(n):
  if(n > 100): pass
  if i % 3 == 0 and i % 5 == 0: print "FizzBuzz"
  elif: i % 3 == 0: print "Fizz"
  elif: i % 5 == 0: print "Buzz"
  else: print i
  fizzbuzz(n+1)


fizzbuzz(1)

Aktiv Gist dette her. ^_^