Created
September 5, 2018 03:09
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run a shell job multiple days
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sdate=$1 #`date -d'-1 days' +"%Y%m%d"` | |
edate=$2 #`date -d'+0 days' +"%Y%m%d"` | |
date=$sdate | |
declare -a date_array=() | |
#先生成日期数组,然后依次遍历数组中的日期 | |
while [ $date -ne $edate ];do | |
echo "date", $date | |
date_array=("${date_array[@]}" $date) | |
date=`date -d"$date 1 day" '+%Y%m%d'` | |
done | |
#打印数组长度,即天数 | |
echo ${#date_array[@]} | |
echo "print date_array" | |
for date in ${date_array[@]}; do | |
echo $date | |
done | |
for date in ${date_array[@]}; do | |
echo $date | |
sh run_real_time.sh $date | |
if [ $? -ne 0 ];then | |
echo "task of $date failed" | |
exit -1 | |
fi | |
done |
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