Fizz Buzz solution

fizzBuzz.js

// Write code to loop through the array of numbers
// At each iteration, if a number is evenly divisible by 3 print "Fizz"
// If a number is evenly divisible by 5 print "Buzz"
// If a number is evenly divisible by both 3 AND 5, print "Fizz Buzz"
// If a number is not divisible by 3 or 5, print the number

const fizzBuzz = function(arr) {
	for (let i in arr) {
		let currentNumber = arr[i];

		if (currentNumber % 15 === 0) {
			console.log('Fizz Buzz');
		} else if (currentNumber % 3 === 0) {
			console.log('Fizz');
		} else if (currentNumber % 5 === 0) {
			console.log('Buzz');
		} else {
			console.log(currentNumber);
		}
	}
};