Implementation of Intersection and Union of integer digits in C

main.c

#include <stdint.h>
#include <stdio.h>
#include <stdbool.h>

bool anyMatch(int32_t num1, int32_t num2) {
	
	while(true) {		
		if ((num2 % 10) == num1) {
			return true;
		}
		if ((num2 / 10) == num2) {
			break;
		}
		num2 /= 10;
	}
	return false;	
}

// 112342 /\ 5612124 = 124
int32_t intersect(int32_t num1, int32_t num2) {
	int32_t matched = 0;

	while(true) {
		if (anyMatch((num1 % 10), num2) && !anyMatch((num1 % 10), matched)) {
			matched = (matched * 10) + (num1 % 10);						
		}
		if ((num1 % 10) == num1) {
			break;
		}
		num1 /= 10;
	}

	return matched;
}

// 112342 \/ 5612124 = 123456
int32_t yunion(int32_t num1, int32_t num2) {
	int32_t yun = 0;

	while(true) {	
		if (!anyMatch((num1 % 10), yun)) {
			yun = (yun * 10) + (num1 % 10);
		}
		if ((num1 % 10) == num1) {
			break;
		}		
		num1 /= 10;
	}

	while(true) {		
		if (!anyMatch((num2 % 10), yun)) {
			yun = (yun * 10) + (num2 % 10);
		}
		if ((num2 % 10) == num2) {
			break;
		}
		num2 /= 10;
	}

	return yun;
}

int main(int argc, char const *argv[])
{
	printf("%d\n", intersect(112342, 5612124));
	printf("%d\n", yunion(112342, 5612124));

	return 0;
}