Created
September 22, 2016 17:27
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IPv6 Shortener in Python
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import re | |
def shorten(ipv6_long): | |
hextets = ipv6_long.split(':') | |
temp = [] | |
for hextet in hextets: | |
# trim leading '0's | |
hextet = re.sub(r'^0+', '', hextet) | |
# lowercase any A-F values | |
hextet = hextet.lower() | |
if 0 == len(hextet): | |
hextet = '0' | |
# append to a temp array | |
temp.append(hextet) | |
tempstr = ':'.join(temp) | |
print "tempstr = %s" % tempstr | |
ipv6_short = re.sub( r'(:0)+', ':', tempstr, 1 ) | |
return ipv6_short | |
ipv6_long = '2604:A880:0001:0020:0000:0000:0ECF:2001' | |
#ipv6_long = '2604:A880:0001:0000:0000:0000:0ECF:2001' | |
ipv6_short = shorten(ipv6_long) | |
print "ipv6 (long) = %s" % ipv6_long | |
print "ipv6 (short) = %s" % ipv6_short | |
solution, based on python3 ipaddress module
def shorten_ipv6(ipv6_long):
hextets = ['%x' % int(h, 16) for h in ipv6_long.split(':')]
best_doublecolon_start = -1
best_doublecolon_len = 0
doublecolon_start = -1
doublecolon_len = 0
for index, hextet in enumerate(hextets):
if hextet == '0':
doublecolon_len += 1
if doublecolon_start == -1:
# Start of a sequence of zeros.
doublecolon_start = index
if doublecolon_len > best_doublecolon_len:
# This is the longest sequence of zeros so far.
best_doublecolon_len = doublecolon_len
best_doublecolon_start = doublecolon_start
else:
doublecolon_len = 0
doublecolon_start = -1
if best_doublecolon_len > 1:
best_doublecolon_end = (best_doublecolon_start +
best_doublecolon_len)
# For zeros at the end of the address.
if best_doublecolon_end == len(hextets):
hextets += ['']
hextets[best_doublecolon_start:best_doublecolon_end] = ['']
# For zeros at the beginning of the address.
if best_doublecolon_start == 0:
hextets = [''] + hextets
return ':'.join(hextets)
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There is no needs to use
re
here:otherwise, my solution is wrong too - we need to merge zeroes from shortest range, not just from left