Quick XOR of hexadecimal strings for BASH

bash_xor.txt

# BASH function to get the result
# of a ^ b when a, b are in the
# following hexadecimal string 
# form: AF396463D8705 ...

# Obtained from here:
# http://www.codeproject.com/Tips/470308/XOR-Hex-Strings-in-Linux-Shell-Script
# Author is Sanjay1982 (see http://www.codeproject.com/Members/Sanjay1982)

# Usage:
# $ xor AB20FF40 DD14FABC

function  xor()
{
	local res=(`echo "$1" | sed "s/../0x& /g"`)
	shift 1
	while [[ "$1" ]]; do
	    local one=(`echo "$1" | sed "s/../0x& /g"`)
	    local count1=${#res[@]}
	    if [ $count1 -lt ${#one[@]} ]
	    then
	          count1=${#one[@]}
	    fi
	    for (( i = 0; i < $count1; i++ ))
	    do
	          res[$i]=$((${one[$i]:-0} ^ ${res[$i]:-0}))
	    done
	    shift 1
	done
	printf "%02x" "${res[@]}"
} 

Nice work. :)

gdb -q -ex 'print/x 0xA ^ 0xF' -ex q