Skip to content

Embed URL

HTTPS clone URL

Subversion checkout URL

You can clone with
or
.
Download ZIP
Matrix population models by Lauren Yamane

A discrete time, age-structured model of a salmon population (semelparous) that can live to age 5, with fishing and environmental stochasticity (by Lauren Yamane, presented to UC Davis R Users' Group)

Parameter values

a=60 #alpha for Beverton-Holt stock-recruitment curve
b=0.00017 #beta for Beverton-Holt
tf=2000 #number of time steps
N0=c(100,0,0,0,0) #initial population vector for 5 age classes
s=0.28 #survival rate with fishing
e=0.1056 #fraction of age 3 fish that spawn early (age 4 is mean spawner age)
l=0.1056 #fraction of age 4 fish that spawn late as age 5 fish
sx=c(s,s,(s*(1-e)),(s*(l))) #survival vector for all ages with fishing, spawners die after spawning
t<-1 #start off at time=1

Make a function for the age-structured matrix

#Make a function for the age-structured matrix with fishing
AgeStructMatrix_F = function(sx,a,b,tf,N0) { 
  sig_r=0.3 
  ncls=length(N0) #Number of age classes
  Nt_F=matrix(0,tf,ncls) #Initialize output matrix with time steps as rows, age classes as columns
  Nt_F[1,]=N0 #put initial values into first row of output matrix
  for(t in 1:(tf-1)) { #for time step t in 1:1999
    Pt= (e*Nt_F[t,3])+((1-l)*Nt_F[t,4])+Nt_F[t,5] #number of spawners
    Nt_F[t+1,1] = ((a*Pt)/(1+(b*Pt)))*(exp(sig_r*rnorm(1,mean=0, sd=1))) #number of recruits with environmental stochasticity
    Nt_F[t+1,2:ncls] = sx*Nt_F[t,1:(ncls-1)] #number of age classes 2-5  
  }
  return(Nt_F)
}

Run model by calling function

Nt_F=AgeStructMatrix_F(sx,a,b,tf,N0) 

Plot of time series with all 5 age classes

matplot(1:tf,Nt_F,type="l",xlab="Time",ylab="Population size", main="Age-structured model with fishing") 

Export text file for plot with age classes

colnames(Nt_F)<-c("Recruits", "Age2", "Age3", "Age4", "Age5") #Rename columns
write.table(Nt_F, "~/Desktop/Nt_F.txt", col.names=TRUE, row.names=FALSE, quote=FALSE, sep=",") #comma separated

Or plot of time series for total population

Nt_F_totals=rowSums(Nt_F)
plot(c(1:tf),Nt_F_totals, type="l",xlab="Time",ylab="Population size", col="blue")

Export text file for plot with total population

write.table(Nt_F_totals, "~/Desktop/Nt_F_totals.txt", col.names=FALSE, row.names=FALSE, quote=FALSE, sep=",")

Stability analysis of deterministic population model

This assumes that the partial differential equations that make up the Jacobian matrix have been determined analytically. Below are the parameters that were associated with my age-structured salmon model with fishing. I can compare the stability of the population with fishing to that with no fishing

e<-0.1056
l<-0.1056
s<-0.28 #survival with fishing
s_noF<-0.85 #survival with no fishing
c<-1/((e*(s^2)+(1-e)*(1-l)*(s^3)+(1-e)*l*(s^4)))
c_noF<-1/((e*(s_noF^2)+(1-e)*(1-l)*(s_noF^3)+(1-e)*l*(s_noF^4)))
alpha<-60 
beta<-0.00017

Fishing Jacobian

one_F<-c(0,0,((alpha*e)/(1+(1/(2*c))*(-c+alpha+sqrt((c-alpha)^2)))^2),((alpha*(1-l))/(1+(1/(2*c))*(-c+alpha+sqrt((c-alpha)^2)))^2),(alpha/(1+(1/(2*c))*(-c+alpha+sqrt((c-alpha)^2)))^2))
two_F<-c(s,0,0,0,0)
three_F<-c(0,s,0,0,0)
four_F<-c(0,0,((1-e)*s),0,0)
five_F<-c(0,0,0,(l*s),0)
jacobian_F<-rbind(one_F,two_F,three_F,four_F,five_F)
jacobian_F

Fishing Eigenvalues

ev_F<-eigen(jacobian_F)
ev1_F=c(Re(ev_F$values[1]),Im(ev_F$values[1]))
ev2_F=c(Re(ev_F$values[2]),Im(ev_F$values[2]))
ev3_F=c(Re(ev_F$values[3]),Im(ev_F$values[3]))
ev4_F=c(Re(ev_F$values[4]),Im(ev_F$values[4]))
ev5_F=c(Re(ev_F$values[5]),Im(ev_F$values[5]))

No Fishing Jacobian

one_noF<-c(0,0,((alpha*e)/(1+(1/(2*c_noF))*(-c_noF+alpha+sqrt((c_noF-alpha)^2)))^2),((alpha*(1-l))/(1+(1/(2*c_noF))*(-c_noF+alpha+sqrt((c_noF-alpha)^2)))^2),(alpha/(1+(1/(2*c_noF))*(-c_noF+alpha+sqrt((c_noF-alpha)^2)))^2))
two_noF<-c(s_noF,0,0,0,0)
three_noF<-c(0,s_noF,0,0,0)
four_noF<-c(0,0,((1-e)*s_noF),0,0)
five_noF<-c(0,0,0,(l*s_noF),0)
jacobian_noF<-rbind(one_noF,two_noF,three_noF,four_noF,five_noF)
jacobian_noF

No Fishing Eigenvalues

ev_noF<-eigen(jacobian_noF)
ev1_noF=c(Re(ev_noF$values[1]),Im(ev_noF$values[1]))
ev2_noF=c(Re(ev_noF$values[2]),Im(ev_noF$values[2]))
ev3_noF=c(Re(ev_noF$values[3]),Im(ev_noF$values[3]))
ev4_noF=c(Re(ev_noF$values[4]),Im(ev_noF$values[4]))
ev5_noF=c(Re(ev_noF$values[5]),Im(ev_noF$values[5]))

# Setup for plot, just remember to expand the plot interface first 
library(plotrix) #load plotrix

Plot the eigenvalues with legend to compare stability of both deterministic models

layout(matrix(c(1,0,2,0,3,0), 2,3, byrow=TRUE)) #Layout with 2 rows, 3 columns,
#the matrix tells you the number of the figure in each location.  
#Since the layout is byrow, it fills the first row first and then the 2nd row
#no fishing plot
plot(ev1_noF[1],ev1_noF[2], type="p", pch=0, cex=2, xlab="Real", ylab="Imaginary", xlim=c(-1.25,1.25),ylim=c(-1.25,1.25)) 
title("No fishing", adj=0) #plot dominant eigenvalue, with x-coordinate as real part and y-coordinate as imaginary part
draw.circle(0,0,radius=1, border="black", lty=1, lwd=1) #draw unit circle
points(ev2_noF[1],ev2_noF[2], pch=1, cex=2) #2nd eigenvalue
points(ev3_noF[1],ev3_noF[2], pch=2, cex=2) #3rd eigenvalue
points(ev4_noF[1],ev4_noF[2], pch=6, cex=2) #4th eigenvalue
points(ev5_noF[1],ev5_noF[2], pch=5, cex=2) #5th eigenvalue
abline(a=NULL, b=NULL, h=0, lty=3)
abline(a=NULL, b=NULL, v=0, lty=3)

#fishing plot
plot(ev1_F[1],ev1_F[2], type="p", pch=0, cex=2, xlab="Real", ylab="Imaginary", xlim=c(-1.25,1.25),ylim=c(-1.25,1.25))
title("Fishing", adj=0)
draw.circle(0,0,radius=1, border="black", lty=1, lwd=1)
points(ev2_F[1],ev2_F[2], pch=1, cex=2)
points(ev3_F[1],ev3_F[2], pch=2, cex=2)
points(ev4_F[1],ev4_F[2], pch=6, cex=2)
points(ev5_F[1],ev5_F[2], pch=5, cex=2)
abline(a=NULL, b=NULL, h=0, lty=3)
abline(a=NULL, b=NULL, v=0, lty=3)

#Legend
plot(1:10, type="n", axes=FALSE, xlab="", ylab="", frame.plot=TRUE)
title("Legend", adj=0)
text(6.5,9.5,expression(lambda[1]), cex=1.2)
text(6.5,7.5,expression(lambda[2]), cex=1.2)
text(6.5,5.5,expression(lambda[3]), cex=1.2)
text(6.5,3.5,expression(lambda[4]), cex=1.2)
text(6.5,1.5,expression(lambda[5]), cex=1.2) 
points(4.5,9.5,pch=0, cex=1.3)
points(4.5,7.5,pch=1, cex=1.3)
points(4.5,5.5,pch=2, cex=1.3)
points(4.5,3.5,pch=6, cex=1.3)
points(4.5,1.5,pch=5, cex=1.3)
Sign up for free to join this conversation on GitHub. Already have an account? Sign in to comment
Something went wrong with that request. Please try again.