beatingHeart.cpp

//改自 如何用C语言画一个“心形”？ - Milo Yip 的回答
//https://www.zhihu.com/question/20187195/answer/34873279
//来个 g++ linux 支援控制代码 改丑了不要找我，不喜勿喷 <(_ _)>
#include <stdio.h>
#include <stdlib.h>
#include <math.h>
#include <unistd.h>
#include <signal.h>
float f(float x, float y, float z) {
    float a = x * x + 9.0f / 4.0f * y * y + z * z - 1;
    return a * a * a - x * x * z * z * z - 9.0f / 80.0f * y * y * z * z * z;
}

float h(float x, float z) {
    for (float y = 1.0f; y >= 0.0f; y -= 0.001f)
        if (f(x, y, z) <= 0.0f)
            return y;
    return 0.0f;
}

void endProg(int msg){
    printf("\33[?25h");
    exit(0);
    return;
}

int main() {
    char buffer[25][80] = { 0 };
    char ramp[] = ".:-=+*#%@";
    signal(SIGINT, endProg);
    printf("\033[?25l");
    for (float t = 0.0f;; t += 0.1f) {
        int sy = 0;
        float s = sinf(t);
        float a = s * s * s * s * 0.2f;
        for (float z = 1.3f; z > -1.2f; z -= 0.1f) {
            char *p = &buffer[sy++][0];
            float tz = z * (1.2f - a);
            for (float x = -1.5f; x < 1.5f; x += 0.05f) {
                float tx = x * (1.2f + a);
                float v = f(tx, 0.0f, tz);
                if (v <= 0.0f) {
                    float y0 = h(tx, tz);
                    float ny = 0.01f;
                    float nx = h(tx + ny, tz) - y0;
                    float nz = h(tx, tz + ny) - y0;
                    float nd = 1.0f / sqrtf(nx * nx + ny * ny + nz * nz);
                    float d = (nx + ny - nz) * nd * 0.5f + 0.5f;
                    *p++ = ramp[(int)(d * 5.0f)];
                }
                else
                    *p++ = ' ';
            }
        }
        for (sy = 0; sy < 25; sy++) {
            printf("\033[40;31m");
            fwrite(buffer[sy] , 79 , 1 , stdout);
            printf("\033[0m\n");
        }
        printf("\033[25A");
        usleep(6000);
    }
}