Created
January 3, 2011 02:46
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| // 1234567 | |
| // racecar | |
| // 0123456 | |
| // >>>X<<< close in on it, only need half the length of word loopage | |
| function is_palindrome(word) { | |
| var outcome = true; | |
| for(i = 0; i <= (word.length / 2); i++) { | |
| //console.log("Comparing " + word[i] + " and " + word[word.length - 1 - i] + "." ); | |
| // always true for palindromes | |
| if(word[i] != word[word.length - 1 - i]) { | |
| outcome = false; | |
| break; | |
| } | |
| } | |
| return outcome; | |
| } |
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Was asked this for a whiteboarding interview once, wanted to give it an honest shot. Is there any more efficient way to do this?