strPos.js

/** Find the number of occurances of a substring within another string, occurances do not need to be
 * in immediate sequence. for example the pattern ab will match with (a)(b)xcy(a)z(b) for an answer of 3
 *
 */
var strPos = function( string, substring ){
    var count = 0;
    if( substring.length > 0 ){
        var pos = 0;
        string.split('').forEach(function(character){
            pos += 1;
            if( character == substring[0] ) {
                count += strPos ( 
                    string.slice( 
                        pos, 
                        string.length 
                    ), substring.slice( 
                        1, 
                        substring.length 
                    ) 
                );
            }
        })
    } else {
        count += 1
    }
    return count;
}