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D3 function for fitting a projection to geodata
function fitProjection(projection, data, box, center) {
// get the bounding box for the data - might be more efficient approaches
var left = Infinity,
bottom = -Infinity,
right = -Infinity,
top = Infinity;
// reset projection
projection
.scale(1)
.translate([0, 0]);
data.features.forEach(function(feature) {
d3.geo.bounds(feature).forEach(function(coords) {
coords = projection(coords);
var x = coords[0],
y = coords[1];
if (x < left) left = x;
if (x > right) right = x;
if (y > bottom) bottom = y;
if (y < top) top = y;
});
});
// project the bounding box, find aspect ratio
function width(bb) {
return (bb[1][0] - bb[0][0])
}
function height(bb) {
return (bb[1][1] - bb[0][1]);
}
function aspect(bb) {
return width(bb) / height(bb);
}
var startbox = [[left, top], [right, bottom]],
a1 = aspect(startbox),
a2 = aspect(box),
widthDetermined = a1 > a2,
scale = widthDetermined ?
// scale determined by width
width(box) / width(startbox) :
// scale determined by height
height(box) / height(startbox),
// set x translation
transX = box[0][0] - startbox[0][0] * scale,
// set y translation
transY = box[0][1] - startbox[0][1] * scale;
console.log(startbox);
// center if requested
if (center) {
if (widthDetermined) {
transY = transY - (transY + startbox[1][1] * scale - box[1][1])/2;
} else {
transX = transX - (transX + startbox[1][0] * scale - box[1][0])/2;
}
}
return projection.scale(scale).translate([transX, transY])
}
@nrabinowitz
Owner

Note: at the moment, this only works for Mercator projections.

@boorad
boorad commented Jun 1, 2012

dude, this saved my life... thanks!

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