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December 16, 2015 19:09
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Find duplicate user ids on a system by parsing the /etc/passwd file
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#!/usr/bin/env python | |
from collections import defaultdict | |
# Initialize dictionary of user ids | |
uids = defaultdict(list) | |
# loop through password file, building dictionary of uid:[list of usernames] | |
with open("/etc/passwd") as passwd_file: | |
for line in passwd_file: | |
line_array = line.split(":") | |
uids[line_array[2]].append(line_array[0]) | |
# loop though dictionary. | |
# If duplicate usernames for uid found, print on standard out | |
for uid in uids: | |
if len(uids[uid]) > 1: | |
print ( uid + ": " + " ".join(uids[uid])) |
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