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December 25, 2023 10:39
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Swift Challenge: Cool Ways to Evaluate Two Bool Variables and Return a Result
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// I have two bool variables. and I want to write a method with this logic: | |
// if two variables are true return .both | |
// and if first variable is true return .first | |
// and if the second one is true return .second | |
// otherwise return .none | |
enum Result { | |
case first | |
case second | |
case both | |
case none | |
} | |
let first = true | |
let second = false | |
// First Approach, with `switch` expression introduced in Swift V 5.9 | |
func evaluateVariables1(_ first: Bool, _ second: Bool) -> Result { | |
switch (first, second) { | |
case (true, true): | |
.both | |
case (true, false): | |
.first | |
case (false, true): | |
.second | |
case (false, false): | |
.none | |
} | |
} | |
print(evaluateVariables1(first, second)) | |
// Second Approach, with ternary operator | |
func evaluateVariables2(_ first: Bool, _ second: Bool) -> Result { | |
first && second ? .both : | |
first ? .first : | |
second ? .second : | |
.none | |
} | |
print(evaluateVariables2(first, second)) | |
// Third Approach, with Swift Tuple and Closure way | |
func evaluateVariables3(_ first: Bool, _ second: Bool) -> Result { | |
[(first && second, Result.both), | |
(first, .first), | |
(second, .second) | |
].first { $0.0 }?.1 ?? .none | |
} | |
print(evaluateVariables3(first, second)) | |
// Forth Approach, with `if` expression introduced in Swift V 5.9 | |
func evaluateVariables4(_ first: Bool, _ second: Bool) -> Result { | |
if first, second { Result.both } else { | |
if first { .first } else { | |
if second { .second } else { | |
.none | |
} | |
} | |
} | |
} | |
print(evaluateVariables4(first, second)) | |
// Fifth Approach, Kinda functional way (using Swift Closures) | |
func evaluateVariables5(_ first: Bool, _ second: Bool) -> Result { | |
{ first ? .first : { second ? .second : { first && second ? .both : .none }() }() } () | |
} | |
print(evaluateVariables5(first, second)) |
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