Print of certain line in the file on Linux

Using perl:
$ perl -ne 'print if $.>=3 and $.<=5;' /etc/passwd
  or 
$ perl -ne 'print if $.>=3; last if $.>5' /etc/passwd
(The second variant is, again, more efficient.)
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Using sed:
$ sed -n '3,5p' /etc/passwd
 or
$ sed -n '3,5p;6q' /etc/passwd
  (The second version would quit upon encountering line 6 so it would be efficient for huge files.)
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Using awk:
$ awk 'NR==3,NR==5' /etc/passwd
 or
$ awk 'NR>=3{print}NR==5{exit}' /etc/passwd
  (The second variant quit after printing line 5 so it's more efficient.)
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Using python:
build script:

with open('yourfile.txt') as f:
    for line in itertools.islice(f, num+1, num+2):
        print line
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Using head:
$ head -5 /etc/passwd | tail -3
(Tail returns the last lines of a file together with a pipe you can use both features.)
  or 
$ head -n 5 /etc/passwd
(The second variant print first five lines.)
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Using bash:
$ find / -type f -name awk.txt & awk 'NR==3' awk.txt | less
 (This is the command to find the file with name "awk.txt" and print the third line from this file.)