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@nubbel
Last active July 4, 2023 13:00
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protocol ArrayRepresentable {
typealias ArrayType
func toArray() -> ArrayType[]
}
extension Range : ArrayRepresentable {
func toArray() -> T[] {
return T[](self)
}
}
(1..5).toArray() // => [1, 2, 3, 4]
(-2.0..2.0).toArray() // => [-2.0, -1.0, 0.0, 1.0]
func toArray<S : Sequence>(seq: S) -> Array<S.GeneratorType.Element> {
return Array<S.GeneratorType.Element>(seq)
}
toArray(1..5) // => [1, 2, 3, 4]
toArray(-2.0..2.0) // => [-2.0, -1.0, 0.0, 1.0]
@kakubei
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kakubei commented Mar 5, 2015

@andy318. Great stuff, thanks a lot! Works great.

@SimplGy
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SimplGy commented Aug 19, 2016

What does this provide above Array(1...42)?

@eonist
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eonist commented Jan 12, 2017

Swift 3?

@keisei1092
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👍

@RomanVolkov
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@eonist
(1...40).map { String($0) }
Swift 3

@eonist
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eonist commented Mar 16, 2017

Meta: I googled this again. And found my self asking the same question. :P

@Gerst20051
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Thanks @RomanVolkov was just about to post that same thing.

@noamtamim
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noamtamim commented May 7, 2017

I found this to be the best option in Swift 3:

Array(0...3)    // [0,1,2,3]
Array(0..<3)    // [0,1,2]

@honghaoz
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honghaoz commented Sep 1, 2020

import Foundation

public extension Range where Bound: Strideable, Bound.Stride: SignedInteger {

  /// Convert to an array.
  func asArray() -> [Bound] {
    Array(self)
  }
}

public extension ClosedRange where Bound: Strideable, Bound.Stride: SignedInteger {

  /// Convert to an array.
  func asArray() -> [Bound] {
    Array(self)
  }
}

public extension Sequence {

  /// Convert to an array.
  func asArray() -> [Iterator.Element] {
    Array(self)
  }
}
(1 ..< 4).asArray() // [1, 2, 3]
(1 ... 4).asArray() // [1, 2, 3, 4]
zip([1, 2, 3], ["a", "b", "c"]).asArray() // [(1, "a"), (2, "b"), (3, "c")]

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