Created
April 15, 2014 22:40
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proof that Control.Lens rules
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name: lens-test | |
version: 0.1 | |
license: AllRightsReserved | |
build-type: Simple | |
cabal-version: >=1.8 | |
executable lens-test | |
hs-source-dirs: . | |
main-is: Test.hs | |
build-depends: base >= 4.5 && < 5 | |
, lens |
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{-# LANGUAGE TemplateHaskell #-} | |
import Control.Lens | |
data A = A { | |
_aId :: Int | |
, _bs :: [B] | |
} deriving (Show) | |
data B = B { | |
_bId :: Int | |
, _rects :: [Rect] | |
} deriving (Show) | |
data Rect = Rect { | |
_left :: Int | |
, _top :: Int | |
, _width :: Int | |
, _height :: Int | |
} deriving (Show) | |
makeLenses ''A | |
makeLenses ''B | |
makeLenses ''Rect | |
area :: Rect -> Int | |
area r = _width r * _height r | |
aRectangles = bs . traverse . rects | |
doubleWidths :: [A] -> [A] | |
doubleWidths = map (\a -> a { _bs = doubleBs . _bs $ a }) | |
where | |
doubleBs = map (\b -> b { _rects = map (\r -> r { _width = 2 * _width r }) . _rects $ b }) | |
t :: [A] | |
t = [A 13 [ B 3 [Rect 0 0 5 10, Rect 1 1 1 1] | |
, B 4 [Rect 1 1 1 1, Rect 1 1 5 5, Rect 2 2 8 8] | |
] | |
] | |
main = do | |
print t | |
print (t ^.. traverse . aRectangles) | |
-- Double width of each rect | |
print ([Rect 0 0 5 5, Rect 1 1 2 2] ^.. traverse) | |
print ([Rect 0 0 5 5, Rect 1 1 2 2] ^.. traverse . width) | |
putStrLn "\ndouble widths of rects" | |
print ([Rect 0 0 5 5, Rect 1 1 2 2] & each . width %~ (*2)) | |
putStrLn "\ndouble widths - map map, ..., map" | |
print . doubleWidths $ t | |
putStrLn "\ndouble widths - each lens" | |
print (t & each . bs . each . rects . each . width %~ (*2)) | |
putStrLn "\nfilter - include only area == 1 rects" | |
print (t & each . bs . each . rects %~ filter (\r -> area r < 2)) |
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