Created
August 3, 2016 18:55
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N - Queens problem: Produces all distinct solutions.
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def nqueens(n): | |
#This version generates all possible solns | |
seen = set() | |
for c in xrange(n): | |
Q = [None] * n | |
attempt = dfs(0, c, Q) | |
if attempt: | |
res = '' | |
for val in Q: | |
res += str(val) | |
seen.add(res) | |
print 'all solns generated number of distinct solns =', len(seen), seen | |
return len(seen) | |
def dfs(r, c, Q): | |
opts = [x for x in xrange(len(Q)) if x != c] | |
opts.append(c) | |
while opts: | |
c = opts.pop() | |
if is_soln(r, c, Q): | |
return True | |
elif is_valid(r, c, Q): | |
emplaceQ(r, c, Q) | |
dive = dfs(r + 1, c, Q) | |
if dive: | |
return True | |
else: | |
removeQ(r, c, Q) | |
return False | |
def emplaceQ(r, c, Q): | |
Q[r] = c | |
def removeQ(r, c, Q): | |
Q[r] = None | |
def is_valid(r, c, Q): | |
row, col = r, c | |
for i in xrange(row): | |
if col == Q[i] or (row - col) == (i - Q[i]) or\ | |
(row + col) == (i + Q[i]): | |
return False | |
return True | |
def is_soln(r, c, Q): | |
row, n = r, len(Q) | |
if (row == n - 1) and is_valid(r, c, Q): | |
emplaceQ(r, c, Q) | |
return True | |
return False | |
nqueens(15) |
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