Created
August 5, 2016 11:53
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Solution to the equilibrium index problem
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| def soln(A): | |
| sumA, prevSum, n = sum(A), 0, len(A) | |
| for i in xrange(n): | |
| rem = sumA - prevSum - A[i] | |
| if prevSum == rem: | |
| return i | |
| else: | |
| prevSum += A[i] | |
| return -1 |
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