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@okunishinishi
Created March 8, 2014 03:12
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Delete all git remote tags
#Delete local tags.
git tag -l | xargs git tag -d
#Fetch remote tags.
git fetch
#Delete remote tags.
git tag -l | xargs -n 1 git push --delete origin
#Delete local tasg.
git tag -l | xargs git tag -d
@markusressel
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I didn't find a solution anywhere that didn't requre a single git push call per tag, so I came up with this variant, which - in my case - reduced the runtime from several hours to several seconds:

git push --delete origin $( git ls-remote --tags origin | awk '{print $2}' | grep -Ev "\^" | tr '\n' ' ')

Explanation

  • git push --delete origin $(...): Deletes a tag (or multiple) on origin
  • $( git ls-remote --tags origin | awk '{print $2}' | grep -Ev "\^" | tr '\n' ' '): Creates a space delimited string of all tags
    • git ls-remote --tags origin: Prints all tags on the remote origin
    • ... | awk '{print $2}' | ...: Only prints the second column of the previous command output
    • ... | grep -Ev "\^" | ...: Filters out unwanted refs/tags/mytag^{} variants (not sure where they come from)
    • ... | tr '\n' ' ': Converts the list into a space delimited string

It takes advantage of the fact that you can provide multiple tag names in a space delimited string, so it only invokes git delete once.

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