Which arithmetic operators in JS can yield a NaN given non-NaN (numeric) operands:

nan.js

"use strict";

const vals = [
    0,(-0),1,-1,Infinity,-Infinity,
];

const binops = [
    "&", "|", "^", ">>", "<<", ">>>",
    "+", "-", "*", "/", "%",
    "&&", "||"
];

for (let op = 0; op < binops.length; op++) {
    for (let i = 0; i < vals.length; i++) {
        for (let j = 0; j < vals.length; j++) {
            const expr = vals[i] +" "+ binops[op] +" "+ vals[j];
            const r = eval(expr);
            if (isNaN(r)) {
                console.log(expr +" -> NaN");
            }
        }
    }
}

Cool! Btw, it outputs many more results if you add a string to the vals array, e.g. '"A"'.

Oh yeah - this is for finding how numerical non-NaN operands can yield NaN. A non-numeric value that is implicitly converted to NaN prior to the arithmetic operation will certainly yield NaN. Clarifying gist description.