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@operator-DD3
Created August 26, 2015 15:07
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[Lua] CryptoPals Cipher Challenge 1-2
local index_table = 'ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz0123456789+/'
function to_binary(integer)
local remaining = tonumber(integer)
local bin_bits = ''
for i = 7, 0, -1 do
local current_power = math.pow(2, i)
if remaining >= current_power then
bin_bits = bin_bits .. '1'
remaining = remaining - current_power
else
bin_bits = bin_bits .. '0'
end
end
return bin_bits
end
function from_binary(bin_bits)
return tonumber(bin_bits, 2)
end
function string.to_base64(to_encode)
local bit_pattern = ''
local encoded = ''
local trailing = ''
for i = 1, string.len(to_encode) do
bit_pattern = bit_pattern .. to_binary(string.byte(string.sub(to_encode, i, i)))
end
-- Check the number of bytes. If it's not evenly divisible by three,
-- zero-pad the ending & append on the correct number of ``=``s.
if math.mod(string.len(bit_pattern), 3) == 2 then
trailing = '=='
bit_pattern = bit_pattern .. '0000000000000000'
elseif math.mod(string.len(bit_pattern), 3) == 1 then
trailing = '='
bit_pattern = bit_pattern .. '00000000'
end
for i = 1, string.len(bit_pattern), 6 do
local byte = string.sub(bit_pattern, i, i+5)
local offset = tonumber(from_binary(byte))
encoded = encoded .. string.sub(index_table, offset+1, offset+1)
end
return string.sub(encoded, 1, -1 - string.len(trailing)) .. trailing
end
function string.from_base64(to_decode)
local padded = to_decode:gsub("%s", "")
local unpadded = padded:gsub("=", "")
local bit_pattern = ''
local decoded = ''
for i = 1, string.len(unpadded) do
local char = string.sub(to_decode, i, i)
local offset, _ = string.find(index_table, char)
if offset == nil then
error("Invalid character '" .. char .. "' found.")
end
bit_pattern = bit_pattern .. string.sub(to_binary(offset-1), 3)
end
for i = 1, string.len(bit_pattern), 8 do
local byte = string.sub(bit_pattern, i, i+7)
decoded = decoded .. string.char(from_binary(byte))
end
local padding_length = padded:len()-unpadded:len()
if (padding_length == 1 or padding_length == 2) then
decoded = decoded:sub(1,-2)
end
return decoded
end
function string.from_hex(str)
return (str:gsub('..', function (cc)
return string.char(tonumber(cc, 16))
end))
end
function string.to_hex(str)
return (str:gsub('.', function (c)
return string.format('%02x', string.byte(c))
end))
end
function fixedXOR(a,b)
local out = ""
for i = 1, #a-1,2 do
a1 = string.sub(a,i,i+1)
b1 = string.sub(b,i,i+1)
a2 = string.byte(a1:from_hex())
b2 = string.byte(b1:from_hex())
out = out .. string.char(bit.bxor(a2,b2))
end
return (out:to_hex())
end
ciphertext = '1c0111001f010100061a024b53535009181c'
key = '686974207468652062756c6c277320657965'
plaintext = fixedXOR(ciphertext,key)
expected = '746865206b696420646f6e277420706c6179'
io.write('\27[1mCryptoPals Cipher Challenge: Set 1-2\27[m\n\n')
io.write('\27[32mCiphertext: \27[m\t',ciphertext,'\n')
io.write('\27[32mKey: \27[m\t\t',key,'\n')
io.write('\27[32mPlaintext: \27[m\t',plaintext,'\n')
io.write('\27[32mExpected:\27[m\t',expected,'\n')
io.write('\27[32mDecoded:\27[m\t',plaintext:from_hex(),'\n')
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