If your sum each letter in a name using a=1, b=2... # will the name be a prime number? Or even better, a palindrome?

isnamepalindromeprime.py

#!/usr/bin/python3
# coding: utf-8
#
# If you sum each letter in a name using a=1, b=2...
# will the name be a prime number? Or even better, a palindrome?
#
import sys


def main():
    '''Convert each character in a name to a number (a=1, b=2..) 
    and check if it is a prime number summed.'''
    
    chars = ['a', 'b', 'c', 'd', 'e', 'f', 'g', 'h', 'i', 'j', 'k', 'l', 'm', 'n', \
        'o', 'p', 'q', 'r', 's', 't', 'u', 'v', 'w', 'x', 'y', 'z', 'æ', 'ø', 'å']

    # Get a name input, can be one or more names
    try:
        input_name = sys.argv[1]
    except:
        input_name = input('Enter a name: ')

    # Clean up name
    input_name_clean = input_name.lower().replace(" ", "").replace("-", "")
    # Check each character againts the alphabet list, and sum it
    sum_name = (sum(chars.index(c) + 1 for c in input_name_clean))

    # Check if the sum is a prime number or not
    if all(sum_name % i for i in range(2, sum_name)):
        # Also, check if number is palindrom
        reverse_name = str(sum_name)[::-1]
        if sum_name == int(reverse_name):
            print("{} is a palindromeprime ({})".format(input_name, str(sum_name)))
        else:
            print("{} is a prime ({})".format(input_name, str(sum_name)))

    else:
        print("{} is not a prime ({})".format(input_name, str(sum_name)))


if __name__ == '__main__':
    main()