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Chance of duplicates in deck — Python
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| import random as r | |
| a=range | |
| l=len | |
| d=list(a(1,15))*4 | |
| t=[] | |
| for i in a(1000000):r.shuffle(d);t.append(int(any(d[i]==d[i+1]for i in a(l((d)))if i<55))) | |
| print(sum(t)/l(t)) |
Gillade shuffle(l) or 0 in samt användandet av zip. Snyggt!
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Python 2.6
from random import*
N=1e6
l=range(13)_4
sum([shuffle(l)or 0in[x-y for x,y in zip(l[1:],l)]for i in[1]_N])/N